[Internet-e-architetture-di-rete] esercizi VLSM IPv4

[Tonino Andrenacci]

###########################
1. esempio fornito
Addr	  1.  2.  3.  4
Mask	255.255.255.  0

Net		1.2.3.0
Broadcast	1.2.3.255
Hosts		2^8-2=254
###########################


###########################
1.
Addr	  0.  1.  2.  3
Mask	255.255.  0.  0

Net		0.1.0.0
Broadcast	0.1.255.255
Hosts		2^16-2=65534
###########################

###########################
2.
Addr	  0.  1.  2.  3
Mask	255.254.  0.  0

Net		0.0.0.0
Broadcast	0.1.255.255
Hosts		2^17-2=131070
###########################

###########################
3.
Addr	  0.  1.  2.  3
Mask	254.  0.  0.  0

Net		0.0.0.0
Broadcast	1.255.255.255
Hosts		2^25-2=33554430
###########################

###########################
4.
Addr	  0.  1.  2.  3
Mask	192.  0.  0.  0

Net		0.0.0.0
Broadcast	63.255.255.255
Hosts		2^30-2=1.073.741.822
###########################

###########################
5.
Addr	  0.  1.  2.  3
Mask	240.  0.  0.  0

Net		0.0.0.0
Broadcast	15.255.255.255
Hosts		2^28-2=268435454
###########################
###########################
6.
Addr	  0.  1.  2.  3
Mask	255.255.255.240


Net		0.1.2.0
Broadcast	0.1.2.15
Hosts		2^4-2=14
###########################
###########################
7.
Addr	  0.  1.  2.  3
Mask	255.255.255.252

Net		0.1.2.0
Broadcast	0.1.2.3
Hosts		2^2-2=2
###########################

###########################
https://www.prado.it/2016/05/21/yet-another-post-about-ipv4-subnetting-non-contiguous-bits-version/
dopo lettura dell'articolo proposto i seguenti esercizi sono più chiari
 8.  
Addr	  0.  1.  2.  3
Mask	255.255.255.  1

Net		0.1.2.1
Broadcast	0.1.2.255
Hosts		2^8/2-2=126 il primo a bit a destra (meno significativo) genera uno spazio di indirizzamento pari o dispari quindi il numero di indirizzi si dimezza
###########################

###########################
9.
Addr	  0.  1.  2.  3
Mask	255.255. 64.  0

Net		0.1.0.0
Broadcast	0.1.191.255
Hosts		bit non contigui due subnet, per il calcolo magari Angiolillo può essermi di aiuto ;-)
###########################

###########################
10.
Addr	  0.  1.  2.  3
Mask	255.255.  0.255

Net		0.1.0.3
Broadcast	0.1.255.3
Hosts		bit non contigui due subnet
###########################


Il 20/05/16 00:52, Antonio Prado via Internet-e-architetture-di-rete ha
scritto:
> cari allievi,
>
> stasera abbiamo conversato degli spazi di indirizzamento IPv4 e IPv6:
> morfologia, notazione, subnetting.
>
> vi propongo ora qualche esercizio che mi raccomando di iniziare sin da
> subito finche' le idee sono fresche.
>
> dunque, come preannunciato, per ciascun indirizzo dato provate a
> calcolare inizio-rete, fine-rete e numero di host numerabili
> (considerato che in IPv4 non sono assegnabili agli host l'indirizzo di
> inizio rete e l'indirizzo di broadcast).
>
> faccio un esempio su come formattare l'esercizio:
>
> ###########################
> 1.
> Addr	  1.  2.  3.  4
> Mask	255.255.255.  0
>
> Net		1.2.3.0
> Broadcast	1.2.3.255
> Hosts		2^8-2=254
> ###########################
>
> ecco gli esercizi:
>
> per i cognomi da A a L:
>
> A-L.
> Addr	  0.  1.  2.  3
> Mask	255.255.  0.  0
> Mask	255.254.  0.  0
> Mask	254.  0.  0.  0
> Mask	192.  0.  0.  0
> Mask	240.  0.  0.  0
> Mask	255.255.255.240
> Mask	255.255.255.252
> Mask	255.255.255.  1
> Mask	255.255. 64.  0
> Mask	255.255.  0.255
>
> per i cognomi da M a Z:
>
> M-Z.
> Addr	129.130.131.132
> Mask	255.255.  0.  0
> Mask	255.254.  0.  0
> Mask	254.  0.  0.  0
> Mask	192.  0.  0.  0
> Mask	240.  0.  0.  0
> Mask	255.255.255.240
> Mask	255.255.255.252
> Mask	255.255.255.  1
> Mask	255.255. 64.  0
> Mask	255.255.  0.255
>
> ovviamente, come al solito, chiunque puo' partecipare alla
> soluzione/discussione
>
> grazie
> --
> antonio
>
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