[Internet-e-architetture-di-rete] IPv6 subnetting

[luigino_pignoloni at yahoo.com]

 IPv6: 2001:DB8:8::F0F7:E8AD/16F:    2001: : : : : : :L:    2001:FFFF:FFFF:FFFF:FFFF:FFFF:FFFF:FFFF  IPv6: 2001:DB8:8::F0F7:E8AD/29F:    2001:DB8:: L:    2001:DBF:FFFF:FFFF: FFFF:FFFF:FFFF:FFFF  IPv6: 2001:DB8:8::F0F7:E8AD/32F:    2001:DB8:8::L:    2001:FFFF:FFFF:FFFF:FFFF:FFFF:FFFF IPv6: 2001:DB8:8::F0F7:E8AD/48F:    2001:DB80:8000::L:    2001:FFFF:FFFF:FFFF:FFFF:FFFF  IPv6: 2001:DB8:8::F0F7:E8AD/56F:    2001:DB80:8000::L:    2001:FF:FFFF:FFFF:FFFF:FFFF IPv6: 2001:DB8:8::F0F7:E8AD/64F:    2001:DB80:8000::L:    2001:FFFF:FFFF:FFFF:FFFF  IPv6: 2001:DB8:8::F0F7:E8AD/80F:    2001:DB80:8000::L:    2001:FFFF:FFFF:FFFF IPv6: 2001:DB8:8::F0F7:E8AD/81F:    2001:DB80:8000::L:    2001:8FFF:FFFF:FFFF IPv6: 2001:DB8:8::F0F7:E8AD/97F:    2001:DB80:8000::L:    2001:7FFF:FFFF IPv6: 2001:DB8:8::F0F7:E8AD/113F:    2001:DB80:8::F0F7:78ADL:    2001:7FFF:  

    Il Giovedì 10 Novembre 2016 8:57, Antonio Prado via Internet-e-architetture-di-rete <internet-e-architetture-di-rete at list.informagiovani.comunesbt.it> ha scritto:
 

 cari allievi,

grazie per la costanza che dimostrate continuando a seguire questi
astratti numeri.

come promesso ecco l'occasione per esercitarsi:

dato il tema 2001:DB8:8::F0F7:E8AD indicare indirizzo di inizio rete e
indirizzo di fine rete secondo i seguenti prefissi

/16
/29
/32
/48
/56
/64
/80
/81
/97
/113

formulare le soluzioni come in esempio

IPv6:     2001:DB8:8::F0F7:E8AD/128
F:    2001:DB8:8::F0F7:E8AD
L:    2001:DB8:8::F0F7:E8AD

vi invito a cominciare il prima possibile
--
antonio

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