[Internet-e-architetture-di-rete] R: riepilogo 20160321 e esercizi

[giorgio.palma at libero.it]

Ecco l'esercizio:

q:0.3.2.1/1
a:0.0.0.0 – 127.255.255.255

q:0.3.2.1/31
a:0.3.2.0 – 0.3.2.1

q:0.3.2.1/17
a:0.3.0.0 – 0.3.127.255

q:0.3.2.1/15
a:0.2.0.0 – 0.3.255.255

q:255.254.0.0 = /15
a:0.2.0.0 – 0.3.255.255

q:224.0.0.0= /3
a:0.0.0.0 – 31.255.255.255

q:255.255.224.0 = /19
a:0.3.0.0 – 0.3.31.255

q:255.255.255.64
a:0.3.2.0 – 0.3.2.191


Ciao a tutti
Giorgio Palma