[Internet-e-architetture-di-rete] Internet-e-architetture-di-rete Digest, Vol 2, Issue 4

[Antonio Prado]

On 3/25/16 5:50 PM, Emanuela Pompei wrote:
> q: 255.0.0.0/1 <http://255.0.0.0/1>
> a:128.0.0.0 - 255.255.255.255
ok

> q: 255.0.0.0/31 <http://255.0.0.0/31>
> a: 255.0.0.0 - 255.0.0.1
ok

> q: 255.0.0.0/17 <http://255.0.0.0/17>
> a: 255.0.0.0 - 255.0.127.255
ok

> q: 255.0.0.0/15 <http://255.0.0.0/15>
> a: 255.0.0.0 - 255.1.255.255
ok

> q: 255.0.0.0    255.254.0.0
> a: 255.0.0.0 -255.1.255.255
ok

> q: 255.0.0.0 224.0.0.0
> a: 224.0.0.0 - 255.255.255.255
ok

> q: 255.0.0.0 255.255.224.0
> a: 255.0.0.0 - 255.0.31.255
ok

> q: 255.0.0.0 255.255.255.64
> a: 255.0.0.0 - 255.0.0.191
ok

> Domanda...
> mauro diceva /1 subnet mask corrispondente 127.0.0.0 
> io ho fatto 10000000.00000000.00000000.00000000 =128.0.0.0
> sbaglio?

non sbagli, ma stavo attendendo le risposte di ambrosio poiche'
l'esercizio e' il loro.

> con /15 ho 2^17 hosts vero?  2^( 32-15) giusto?
eh si'

(occhio alle e-mail: hai risposto al digesto e non a quella di inizio
thread)

ciao
--
antonio

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