[Internet-e-architetture-di-rete] esercizi IPv6
Mauro Angiolillo
m.angiolillo at comuneap.gov.it
Mon Apr 4 23:36:13 CEST 2016
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Salve prof. procedo alla soluzione del mio esercizio, sperando di non commettere errori:
> angiolillo: 2001::/3 fe80::e6ce:8fff:fe3c:45b6/27 fe80::e6ce:8fff:fe3c:45b6/121
- -------------------------------------------------------
2001::/3
Forma espansa: 2001:0000:0000:00000:0000:0000:0000:0000
Range IP: 2000:0000:0000:00000:0000:0000:0000:0000
3fff:ffff:ffff:fffff:ffff:ffff:ffff:ffff
- -------------------------------------------------------
fe80::e6ce:8fff:fe3c:45b6/27
Forma espansa: fe80:0000:0000:0000:e6ce:8fff:fe3c:45b6
Range IP: fe80:0000:0000:0000:0000:0000:0000:0000
fe80:001f:ffff:ffff:ffff:ffff:ffff:ffff
- ------------------------------------------------------
fe80::e6ce:8fff:fe3c:45b6/121
Forma espansa: fe80:0000:0000:0000:e6ce:8fff:fe3c:45b6
Range IP : fe80:0000:0000:0000:e6ce:8fff:fe3c:4580
fe80:0000:0000:0000:e6ce:8fff:fe3c:45ff
Buona serata,
Mauro
- --
Dott. Ing. Mauro Angiolillo
Linux Registered User #343216
GnuPG-Key fingerprint = 90A3 3F92 6008 7383 A569 E952 CF97 383B 63F6 F425
-*-
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